9x+3+x^2=0

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Solution for 9x+3+x^2=0 equation: 



9x+3+x^2=0

a = 1; b = 9; c = +3;
Δ = b2-4ac
Δ = 92-4·1·3
Δ = 69
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{69}}{2*1}=\frac{-9-\sqrt{69}}{2}
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{69}}{2*1}=\frac{-9+\sqrt{69}}{2}
$

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